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How to get the first and last date of the current year?

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How do I get last year's first date in SQL?

The arguments for DATEADD are DATEADD(interval, increment int, expression smalldatetime). So in the expression above, the DATEDIFF function returns an integer, being the difference in years between the current date and date zero (0). The expression in the above statement accepts a zero (0) as a smalldatetime.

How do I get the year end in SQL?

This works by figuring out the number of years since 1900 with DATEDIFF(yy, 0, GETDATE()) and then adding that to a date of zero = Jan 1, 1900. This can be changed to work for an arbitrary date by replacing the GETDATE() portion or an arbitrary year by replacing the DATEDIFF(...) function with "Year - 1900."

How do I get the first day of my current month?

1. First day of current month: select DATEADD(mm, DATEDIFF(m,0,GETDATE()),0): in this we have taken out the difference between the months from 0 to current date and then add the difference in 0 this will return the first day of current month.


SELECT
   DATEADD(yy, DATEDIFF(yy, 0, GETDATE()), 0) AS StartOfYear,
   DATEADD(yy, DATEDIFF(yy, 0, GETDATE()) + 1, -1) AS EndOfYear

The above query gives a datetime value for midnight at the beginning of December 31. This is about 24 hours short of the last moment of the year. If you want to include time that might occur on December 31, then you should compare to the first of the next year, with a < comparison. Or you can compare to the last few milliseconds of the current year, but this still leaves a gap if you are using something other than DATETIME (such as DATETIME2):

SELECT
   DATEADD(yy, DATEDIFF(yy, 0, GETDATE()), 0) AS StartOfYear,
   DATEADD(yy, DATEDIFF(yy, 0, GETDATE()) + 1, -1) AS LastDayOfYear,
   DATEADD(yy, DATEDIFF(yy, 0, GETDATE()) + 1, 0) AS FirstOfNextYear,
   DATEADD(ms, -3, DATEADD(yy, DATEDIFF(yy, 0, GETDATE()) + 1, 0)) AS LastTimeOfYear

Other Periods

This approach has two nice aspects: good performance and it can easily be changed for other periods by replacing both occurrences of yy (=year) with a different string:

yy, yyyy    year
qq, q       quarter
mm, m       month
wk, ww      week 

(Be careful of weeks: the starting day depends on server settings.)

Tech Details

This works by figuring out the number of years since 1900 with DATEDIFF(yy, 0, GETDATE()) and then adding that to a date of zero = Jan 1, 1900. This can be changed to work for an arbitrary date by replacing the GETDATE() portion or an arbitrary year by replacing the DATEDIFF(...) function with "Year - 1900."

 SELECT
   DATEADD(yy, DATEDIFF(yy, 0, '20150301'), 0) AS StartOfYearForMarch2015,
   DATEADD(yy, 2015 - 1900, 0) AS StartOfYearFor2015

Here's a fairly simple way;

SELECT DATEFROMPARTS(YEAR(GETDATE()), 1, 1) AS 'First Day of Current Year';
SELECT DATEFROMPARTS(YEAR(GETDATE()), 12, 31) AS 'End of Current Year';

It's not sexy, but it works.


You can get the current year using DATEPART function, from the current date obtained using getUTCDate()

SELECT 
    '01/01/' + CONVERT(VARCHAR(4), DATEPART(yy, getUTCDate())), 
    '31/12/' + CONVERT(VARCHAR(4), DATEPART(yy, getUTCDate()))

simply write:-

select convert (date,DATEADD(YEAR,DATEDIFF(YEAR,0,GETDATE()),0))

start date of the year.

select convert (date,DATEADD(YEAR, DATEDIFF(YEAR,0,GETDATE()) + 1, -1))  

Every year has the 1 st as First date and 31 as the last date what you have to do is only attach the year to that day and month for example:-

 SELECT '01/01/'+cast(year(getdate()) as varchar(4)) as [First Day],
 '12/31/'+cast(year(getdate()) as varchar(4)) as [Last Day]

To get the first and the last day of the year, one can use the CONCAT function. The resulting value may be cast to any type.

CONCAT(YEAR(Getdate()),'-01-01') FirstOfYear,
CONCAT(YEAR(GETDATE()),'-12-31') LastOfYear

Another way: (Since SQL Server 2012)

SELECT
    DATEFROMPARTS(YEAR(GETDATE()), 1, 1) FirstDay,
    DATEFROMPARTS(YEAR(GETDATE()),12,31) LastDay