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Can anyone tell me how to get the filename without the extension? Example:
fileNameWithExt = "test.xml"; fileNameWithOutExt = "test"; 
910
GetFileNameWithoutExtension(ReadOnlySpan<Char>) Returns the file name without the extension of a file path that is represented by a read-only character span.
If you are using the Gauva Library, you can directly use the getFileExtension() method to get the file extension. For example, String fileName = "Test. java"; String extension = Files.
Searching files in Java can be performed using the File class and FilenameFilter interface. The FilenameFilter interface is used to filter files from the list of files. This interface has a method boolean accept(File dir, String name) that is implemented to find the desired files from the list returned by the java. io.
If you, like me, would rather use some library code where they probably have thought of all special cases, such as what happens if you pass in null or dots in the path but not in the filename, you can use the following:
import org.apache.commons.io.FilenameUtils; String fileNameWithOutExt = FilenameUtils.removeExtension(fileNameWithExt); If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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