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How to get the filename without the extension from a path in Python?
For instance, if I had "/path/to/some/file.txt", I would want "file".
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Use the substring() method to get the filename without the path, e.g. fullPath. substring(fullPath. lastIndexOf('/') + 1) . The substring method will return a new string containing only the characters after the last slash.
To get a filename from a path in Python, use the os. path. basename() function.
You can extract the file extension of a filename string using the os. path. splitext method. It splits the pathname path into a pair (root, ext) such that root + ext == path, and ext is empty or begins with a period and contains at most one period.
Getting the name of the file without the extension:
import os print(os.path.splitext("/path/to/some/file.txt")[0]) Prints:
/path/to/some/file Documentation for os.path.splitext.
Important Note: If the filename has multiple dots, only the extension after the last one is removed. For example:
import os print(os.path.splitext("/path/to/some/file.txt.zip.asc")[0]) Prints:
/path/to/some/file.txt.zip See other answers below if you need to handle that case.
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