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How to get SciPy.integrate.odeint to stop when path is closed?

edit: It's been five years, has SciPy.integrate.odeint learned to stop yet?


The script below integrates magnetic field lines around closed paths and stops when it returns to original value within some tolerance, using Runge-Kutta RK4 in Python. I would like to use SciPy.integrate.odeint, but I can not see how I can tell it to stop when the path is approximately closed.

Of course odeint may be much faster than integrating in Python, I could just let it go around blindly and look for closure in the results, but in the future I'll do much larger problems.

Is there a way that I can implement a "OK that's close enough - you can stop now!" method into odeint? Or should I just integrate for a while, check, integrate more, check...

This discussion seems relevant, and seems to suggest that "you can't from within SciPy" might be the answer.

Note: I usually use RK45 (Runge-Kutta-Fehlberg) which is more accurate at a given steop size to speed it up, but I kept it simple here. It also makes variable step size possible.

Update: But sometimes I need fixed step size. I've found that Scipy.integrate.ode does provide a testing/stopping method ode.solout(t, y) but doesn't seem to have the ability to evaluate at fixed points of t. odeint allows evaluation at fixed points of t, but doesn't seem to have a testing/stopping method.

enter image description here

def rk4Bds_stops(x, h, n, F, fclose=0.1):

    h_over_two, h_over_six = h/2.0, h/6.0

    watching = False
    distance_max = 0.0
    distance_old = -1.0

    i = 0

    while i < n and not (watching and greater):

        k1 = F( x[i]                )
        k2 = F( x[i] + k1*h_over_two)
        k3 = F( x[i] + k2*h_over_two)
        k4 = F( x[i] + k3*h         )

        x[i+1] = x[i] + h_over_six * (k1 + 2.*(k2 + k3) + k4)

        distance = np.sqrt(((x[i+1] - x[0])**2).sum())
        distance_max = max(distance, distance_max)
        getting_closer = distance < distance_old

        if getting_closer and distance < fclose*distance_max: 
            watching = True

        greater = distance > distance_old
        distance_old = distance

        i += 1

    return i


def get_BrBztanVec(rz):

    Brz = np.zeros(2)

    B_zero = 0.5 * i * mu0 / a
    zz    = rz[1] - h
    alpha = rz[0] / a
    beta  = zz / a
    gamma = zz / rz[0]

    Q = ((1.0 + alpha)**2 + beta**2)
    k = np.sqrt(4. * alpha / Q)

    C1 =    1.0 / (pi * np.sqrt(Q))
    C2 = gamma  / (pi * np.sqrt(Q))
    C3 = (1.0 - alpha**2 - beta**2) / (Q - 4.0*alpha)
    C4 = (1.0 + alpha**2 + beta**2) / (Q - 4.0*alpha)

    E, K = spe.ellipe(k**2), spe.ellipk(k**2)

    Brz[0] += B_zero * C2 * (C4*E - K) 
    Brz[1] += B_zero * C1 * (C3*E + K)

    Bmag = np.sqrt((Brz**2).sum())

    return Brz/Bmag


import numpy as np
import matplotlib.pyplot as plt
import scipy.special as spe
from scipy.integrate import odeint as ODEint

pi = np.pi
mu0 = 4.0 * pi * 1.0E-07

i = 1.0 # amperes
a = 1.0 # meters
h = 0.0 # meters

ds = 0.04  # step distance (meters)

r_list, z_list, n_list = [], [], []
dr_list, dz_list = [], []

r_try = np.linspace(0.15, 0.95, 17)

x = np.zeros((1000, 2))

nsteps = 500

for rt in r_try:

    x[:] = np.nan

    x[0] = np.array([rt, 0.0])

    n = rk4Bds_stops(x, ds, nsteps, get_BrBztanVec)

    n_list.append(n)

    r, z = x[:n+1].T.copy()  # make a copy is necessary

    dr, dz = r[1:] - r[:-1], z[1:] - z[:-1]
    r_list.append(r)
    z_list.append(z)
    dr_list.append(dr)
    dz_list.append(dz)

plt.figure(figsize=[14, 8])
fs = 20

plt.subplot(2,3,1)
for r in r_list:
    plt.plot(r)
plt.title("r", fontsize=fs)

plt.subplot(2,3,2)
for z in z_list:
    plt.plot(z)
plt.title("z", fontsize=fs)

plt.subplot(2,3,3)
for r, z in zip(r_list, z_list):
    plt.plot(r, z)
plt.title("r, z", fontsize=fs)

plt.subplot(2,3,4)
for dr, dz in zip(dr_list, dz_list):
    plt.plot(dr, dz)
plt.title("dr, dz", fontsize=fs)

plt.subplot(2, 3, 5)
plt.plot(n_list)
plt.title("n", fontsize=fs)

plt.show()
like image 872
uhoh Avatar asked Oct 12 '15 02:10

uhoh


1 Answers

What you need is 'event handling'. The scipy.integrate.odeint cannot do this yet. But you could use sundials (see https://pypi.python.org/pypi/python-sundials/0.5), which can do event handling.

The other option, keeping speed as a priority, is to simply code up rkf in cython. I have an implementation lying around which should be easy to change to stop after some criteria:

cythoncode.pyx

import numpy as np
cimport numpy as np
import cython
#cython: boundscheck=False
#cython: wraparound=False

cdef double a2  =   2.500000000000000e-01  #  1/4
cdef double a3  =   3.750000000000000e-01  #  3/8
cdef double a4  =   9.230769230769231e-01  #  12/13
cdef double a5  =   1.000000000000000e+00  #  1
cdef double a6  =   5.000000000000000e-01  #  1/2

cdef double b21 =   2.500000000000000e-01  #  1/4
cdef double b31 =   9.375000000000000e-02  #  3/32
cdef double b32 =   2.812500000000000e-01  #  9/32
cdef double b41 =   8.793809740555303e-01  #  1932/2197
cdef double b42 =  -3.277196176604461e+00  # -7200/2197
cdef double b43 =   3.320892125625853e+00  #  7296/2197
cdef double b51 =   2.032407407407407e+00  #  439/216
cdef double b52 =  -8.000000000000000e+00  # -8
cdef double b53 =   7.173489278752436e+00  #  3680/513
cdef double b54 =  -2.058966861598441e-01  # -845/4104
cdef double b61 =  -2.962962962962963e-01  # -8/27
cdef double b62 =   2.000000000000000e+00  #  2
cdef double b63 =  -1.381676413255361e+00  # -3544/2565
cdef double b64 =   4.529727095516569e-01  #  1859/4104
cdef double b65 =  -2.750000000000000e-01  # -11/40

cdef double r1  =   2.777777777777778e-03  #  1/360
cdef double r3  =  -2.994152046783626e-02  # -128/4275
cdef double r4  =  -2.919989367357789e-02  # -2197/75240
cdef double r5  =   2.000000000000000e-02  #  1/50
cdef double r6  =   3.636363636363636e-02  #  2/55

cdef double c1  =   1.157407407407407e-01  #  25/216
cdef double c3  =   5.489278752436647e-01  #  1408/2565
cdef double c4  =   5.353313840155945e-01  #  2197/4104
cdef double c5  =  -2.000000000000000e-01  # -1/5

cdef class cyfunc:
    cdef double dy[2]

    cdef double* f(self,  double* y):    
        return self.dy
    def __cinit__(self):
        pass

@cython.cdivision(True)
@cython.boundscheck(False)
@cython.wraparound(False)
cpdef rkf(cyfunc f, np.ndarray[double, ndim=1] times, 
          np.ndarray[double, ndim=1] x0, 
          double tol=1e-7, double dt_max=-1.0, double dt_min=1e-8):

    # Initialize
    cdef double t = times[0]
    cdef int times_index = 1
    cdef int add = 0
    cdef double end_time = times[len(times) - 1]
    cdef np.ndarray[double, ndim=1] res = np.empty_like(times)
    res[0] = x0[1] # Only storing second variable
    cdef double x[2]
    x[:] = x0

    cdef double k1[2]
    cdef double k2[2]
    cdef double k3[2]
    cdef double k4[2]
    cdef double k5[2]
    cdef double k6[2]
    cdef double r[2]

    while abs(t - times[times_index]) < tol: # if t = 0 multiple times
        res[times_index] = res[0]
        t = times[times_index]
        times_index += 1

    if dt_max == -1.0:
        dt_max = 5. * (times[times_index] - times[0])
    cdef double dt = dt_max/10.0
    cdef double tolh = tol*dt

    while t < end_time:
        # If possible, step to next time to save
        if t + dt >= times[times_index]:
            dt = times[times_index] - t;
            add = 1

        # Calculate Runga Kutta variables
        k1 = f.f(x)
        k1[0] *= dt; k1[1] *= dt; 
        r[0] = x[0] + b21 * k1[0]
        r[1] = x[1] + b21 * k1[1]

        k2 = f.f(r)
        k2[0] *= dt; k2[1] *= dt; 
        r[0] = x[0] + b31 * k1[0] + b32 * k2[0]
        r[1] = x[1] + b31 * k1[1] + b32 * k2[1]

        k3 = f.f(r)
        k3[0] *= dt; k3[1] *= dt; 
        r[0] = x[0] + b41 * k1[0] + b42 * k2[0] + b43 * k3[0]
        r[1] = x[1] + b41 * k1[1] + b42 * k2[1] + b43 * k3[1]

        k4 = f.f(r)
        k4[0] *= dt; k4[1] *= dt; 
        r[0] = x[0] + b51 * k1[0] + b52 * k2[0] + b53 * k3[0] + b54 * k4[0]
        r[1] = x[1] + b51 * k1[1] + b52 * k2[1] + b53 * k3[1] + b54 * k4[1]

        k5 = f.f(r)
        k5[0] *= dt; k5[1] *= dt;
        r[0] = x[0] + b61 * k1[0] + b62 * k2[0] + b63 * k3[0] + b64 * k4[0] + b65 * k5[0]
        r[1] = x[1] + b61 * k1[1] + b62 * k2[1] + b63 * k3[1] + b64 * k4[1] + b65 * k5[1]

        k6 = f.f(r)
        k6[0] *= dt; k6[1] *= dt;

        # Find largest error
        r[0] = abs(r1 * k1[0] + r3 * k3[0] + r4 * k4[0] + r5 * k5[0] + r6 * k6[0])
        r[1] = abs(r1 * k1[1] + r3 * k3[1] + r4 * k4[1] + r5 * k5[1] + r6 * k6[1])
        if r[1] > r[0]:
            r[0] = r[1]

        # If error is smaller than tolerance, take step
        tolh = tol*dt
        if r[0] <= tolh:
            t = t + dt
            x[0] = x[0] + c1 * k1[0] + c3 * k3[0] + c4 * k4[0] + c5 * k5[0]
            x[1] = x[1] + c1 * k1[1] + c3 * k3[1] + c4 * k4[1] + c5 * k5[1]
            # Save if at a save time index
            if add:
                while abs(t - times[times_index]) < tol:
                    res[times_index] = x[1]
                    t = times[times_index]
                    times_index += 1
                add = 0

        # Update time stepping
        dt = dt * min(max(0.84 * ( tolh / r[0] )**0.25, 0.1), 4.0)
        if dt > dt_max:
            dt = dt_max
        elif dt < dt_min:  # Equations are too stiff
            return res*0 - 100 # or something

        # ADD STOPPING CONDITION HERE...

    return res

cdef class F(cyfunc):
    cdef double a

    def __init__(self, double a):
        self.a = a

    cdef double* f(self, double y[2]):
        self.dy[0] = self.a*y[1] - y[0]
        self.dy[1] = y[0] - y[1]**2

        return self.dy

The code can be run by

test.py

import numpy as np 
import matplotlib.pyplot as plt
import pyximport
pyximport.install(setup_args={'include_dirs': np.get_include()})
from cythoncode import rkf, F

x0 = np.array([1, 0], dtype=np.float64)
f = F(a=0.1)

t = np.linspace(0, 30, 100)
y = rkf(f, t, x0)

plt.plot(t, y)
plt.show()
like image 161
Julius Avatar answered Oct 20 '22 01:10

Julius