How to get request's URI from WebRequest in Spring?

Question

I am handling REST exceptions using @ControllerAdvice and ResponseEntityExceptionHandler in a spring Rest webservice. So far everything was working fine until I decided to add the URI path(for which exception has occurred) into the BAD_REQUEST response.

@ControllerAdvice
public class RestResponseEntityExceptionHandler extends ResponseEntityExceptionHandler {

@Override
protected ResponseEntity<Object> handleHttpMessageNotReadable(HttpMessageNotReadableException ex,
        HttpHeaders headers, HttpStatus status, WebRequest request) {
    logger.info(request.toString());
    return handleExceptionInternal(ex, errorMessage(HttpStatus.BAD_REQUEST, ex, request), headers, HttpStatus.BAD_REQUEST, request);
}

private ApiError errorMessage(HttpStatus httpStatus, Exception ex, WebRequest request) {
    final String message = ex.getMessage() == null ? ex.getClass().getName() : ex.getMessage();
    final String developerMessage = ex.getCause() == null ? ex.toString() : ex.getCause().getMessage();
    return new ApiError(httpStatus.value(), message, developerMessage, System.currentTimeMillis(), request.getDescription(false));
}

ApiError is just a Pojo class:

public class ApiError {

    private Long timeStamp;
    private int status;
    private String message;
    private String developerMessage;
    private String path;
}

But WebRequest has not given any api to get the path for which the request failed. I tried: request.toString() returns -> ServletWebRequest: uri=/signup;client=0:0:0:0:0:0:0:1
request.getDescription(false) returns -> uri=/signup
getDescription is pretty close to the requirement, but doesn't meet it. Is there any way to get only the uri part?

Answer 1

Found the solution. Casting WebRequest to ServletWebRequest solved the purpose.

((ServletWebRequest)request).getRequest().getRequestURI().toString()

returns the complete path - http://localhost:8080/signup

Answer 2

There are multiple solutions to this problem.

1) One can get request URI and client information from WebRequest using webRequest.getDescription(true).

true will show user's information such as client id and false will just print URI.

2) Instead of WebRequest of Use HttpServletRequest directly in method definition as

@Override
protected ResponseEntity<Object> handleHttpMessageNotReadable(HttpMessageNotReadableException ex,
        HttpHeaders headers, HttpStatus status, WebRequest request, HttpServletRequest httpRequest) {
    logger.info(httpRequest.getRequestURI());
    return handleExceptionInternal(ex, errorMessage(HttpStatus.BAD_REQUEST, ex, request), headers, HttpStatus.BAD_REQUEST, request);
}