How to get output of grep in single line in shell script?

Question

Here is a script which reads words from the file replaced.txt and displays the output each word in each line, But I want to display all the outputs in a single line.

#!/bin/sh
 echo
 echo "Enter the word to be translated"
 read a
IFS=" "     # Set the field separator
set $a      # Breaks the string into $1, $2, ...
for a    # a for loop by default loop through $1, $2, ...
    do
    {
    b= grep "$a" replaced.txt | cut -f 2 -d" " 
    }
    done 

Content of "replaced.txt" file is given below:

hllo HELLO
m AM
rshbh RISHABH
jn JAIN
hw HOW 
ws WAS 
ur YOUR
dy DAY

This question can't be appropriate to what I asked, I just need the help to put output of the script in a single line.

Answer 1

Your entire script can be replaced by:

#!/bin/bash
echo
read -r -p "Enter the words to be translated: " a
echo $(printf "%s\n" $a | grep -Ff - replaced.txt | cut -f 2 -d ' ')

No need for a loop.

The echo with an unquoted argument removes embedded newlines and replaces each sequence of multiple spaces and/or tabs with one space.