How to get only part of URL from HttpServletRequest?

Question

From the following URL I need to get (http://localhost:9090/dts) alone.
That is I need to remove (documents/savedoc) (OR)
need to get only - (http://localhost:9090/dts)

http://localhost:9090/dts/documents/savedoc   

Is there any method available in request to get the above?

I tried the following and got the result. But still trying.

System.out.println("URL****************"+request.getRequestURL().toString());   System.out.println("URI****************"+request.getRequestURI().toString()); System.out.println("ContextPath****************"+request.getContextPath().toString());  URL****************http://localhost:9090/dts/documents/savedoc   URI****************/dts/documents/savedoc   ContextPath****************/dts 

Can anyone please help me in fixing this?

Answer 1

You say you want to get exactly:

http://localhost:9090/dts 

In your case, the above string consist of:

1. scheme: http
2. server host name: localhost
3. server port: 9090
4. context path: dts

(More info about the elements of a request path can be found in the official Oracle Java EE Tutorial: Getting Information from Requests)
##First variant:###

String scheme = request.getScheme(); String serverName = request.getServerName(); int serverPort = request.getServerPort(); String contextPath = request.getContextPath();  // includes leading forward slash  String resultPath = scheme + "://" + serverName + ":" + serverPort + contextPath; System.out.println("Result path: " + resultPath); 

##Second variant:##

String scheme = request.getScheme(); String host = request.getHeader("Host");        // includes server name and server port String contextPath = request.getContextPath();  // includes leading forward slash  String resultPath = scheme + "://" + host + contextPath; System.out.println("Result path: " + resultPath); 

---

Both variants will give you what you wanted: http://localhost:9090/dts

Of course there are others variants, like others already wrote ...

It's just in your original question you asked about how to get http://localhost:9090/dts, i.e. you want your path to include scheme.

In case you still doesn't need a scheme, the quick way is:

String resultPath = request.getHeader("Host") + request.getContextPath(); 

And you'll get (in your case): localhost:9090/dts