Download Attachments from gmail using Gmail API

Question

I am using Gmail API to access my Gmail data and Google Python API client.

According to documentation to get the message attachment they gave one sample for Python. But the same code I tried then I am getting an error:

AttributeError: 'Resource' object has no attribute 'user'

The line where I am getting error:

message = service.user().messages().get(userId=user_id, id=msg_id).execute() 

So I tried users() by replacing user():

message = service.users().messages().get(userId=user_id, id=msg_id).execute() 

But I am not getting part['body']['data'] in for part in message['payload']['parts'].

Answer 1

Expanding @Eric answer, I wrote the following corrected version of GetAttachments function from the docs:

# based on Python example from  # https://developers.google.com/gmail/api/v1/reference/users/messages/attachments/get # which is licensed under Apache 2.0 License  import base64 from apiclient import errors  def GetAttachments(service, user_id, msg_id):     """Get and store attachment from Message with given id.      :param service: Authorized Gmail API service instance.     :param user_id: User's email address. The special value "me" can be used to indicate the authenticated user.     :param msg_id: ID of Message containing attachment.     """     try:         message = service.users().messages().get(userId=user_id, id=msg_id).execute()          for part in message['payload']['parts']:             if part['filename']:                 if 'data' in part['body']:                     data = part['body']['data']                 else:                     att_id = part['body']['attachmentId']                     att = service.users().messages().attachments().get(userId=user_id, messageId=msg_id,id=att_id).execute()                     data = att['data']                 file_data = base64.urlsafe_b64decode(data.encode('UTF-8'))                 path = part['filename']                  with open(path, 'w') as f:                     f.write(file_data)      except errors.HttpError, error:         print 'An error occurred: %s' % error 

Answer 2

You can still miss attachments by following @Ilya V. Schurov or @Cam T answers, the reason is because the email structure can be different based on the mimeType.

Inspired by this answer, here is my approach to the problem.

import base64 from apiclient import errors  def GetAttachments(service, user_id, msg_id, store_dir=""):     """Get and store attachment from Message with given id.         Args:             service: Authorized Gmail API service instance.             user_id: User's email address. The special value "me"                 can be used to indicate the authenticated user.             msg_id: ID of Message containing attachment.             store_dir: The directory used to store attachments.     """     try:         message = service.users().messages().get(userId=user_id, id=msg_id).execute()         parts = [message['payload']]         while parts:             part = parts.pop()             if part.get('parts'):                 parts.extend(part['parts'])             if part.get('filename'):                 if 'data' in part['body']:                     file_data = base64.urlsafe_b64decode(part['body']['data'].encode('UTF-8'))                     #self.stdout.write('FileData for %s, %s found! size: %s' % (message['id'], part['filename'], part['size']))                 elif 'attachmentId' in part['body']:                     attachment = service.users().messages().attachments().get(                         userId=user_id, messageId=message['id'], id=part['body']['attachmentId']                     ).execute()                     file_data = base64.urlsafe_b64decode(attachment['data'].encode('UTF-8'))                     #self.stdout.write('FileData for %s, %s found! size: %s' % (message['id'], part['filename'], attachment['size']))                 else:                     file_data = None                 if file_data:                     #do some staff, e.g.                     path = ''.join([store_dir, part['filename']])                     with open(path, 'w') as f:                         f.write(file_data)     except errors.HttpError as error:         print 'An error occurred: %s' % error