How to get numeric position of alphabets in java? [duplicate]

Question

How to get numeric position of alphabets in java ?

Suppose through command prompt i have entered abc then as a output i need to get 123 how can i get the numeric position of alphabets in java?

Thanks in advance.

Answer 1

String str = "abcdef"; char[] ch  = str.toCharArray(); for(char c : ch){     int temp = (int)c;     int temp_integer = 96; //for lower case     if(temp<=122 & temp>=97)         System.out.print(temp-temp_integer); } 

Output:

123456

@Shiki for Capital/UpperCase letters use the following code:

String str = "DEFGHI"; char[] ch  = str.toCharArray(); for(char c : ch){     int temp = (int)c;     int temp_integer = 64; //for upper case     if(temp<=90 & temp>=65)         System.out.print(temp-temp_integer); } 

Output:

456789

Answer 2

Another way to do this problem besides using ASCII conversions is the following:

String input = "abc".toLowerCase(); final static String alphabet = "abcdefghijklmnopqrstuvwxyz"; for(int i=0; i < input.length(); i++){     System.out.print(alphabet.indexOf(input.charAt(i))+1); }