I want to get list of Auth0 users from Java API (auth0 client). Can i do it? API based on Java+Spring Security. I have tried to do it with RestTemplate:
List findAllUsers(){
String idToken = RestService.getIdToken()
HttpHeaders headers = new HttpHeaders()
headers.set("Authorization", "Bearer $idToken");
List users = []
try{
ResponseEntity entity = restTemplate.exchange(issuer+"api/v2/users", HttpMethod.GET, new HttpEntity<Object>(headers), List)
users = entity.getBody()
} catch (HttpClientErrorException e){
e.printStackTrace()
}
return users
}
But i'm getting 403 Forbidden status.
Yes, this is possible. However, you shall need to use an Auth0 Management Token
.
See this sample I wrote, where I do a search (in this case filtering to get a specific user account rather than all users).
You can get Management Token and see the search options here. You need to give your management token read:users
and read:user_idp_tokens
scopes as per docs.
Would recommend you start by using a tool like Postman to get the correct search, then convert to Java. You can use the snippet and associated dependencies listed in the sample link above OkHttpClient
<dependency>
<groupId>com.squareup.okhttp3</groupId>
<artifactId>okhttp</artifactId>
<version>3.2.0</version>
</dependency>
Also, Postman can be used to generate
the code from the request you define too. Auth0 currently does not provide a Management API for Java library, but will do so soon.
Update:
Here is some working code, just replace with your Management Token and Tenant (for the URL).
import com.squareup.okhttp.OkHttpClient;
import com.squareup.okhttp.Request;
import com.squareup.okhttp.Response;
import java.io.IOException;
/**
* Created by arcseldon on 07/09/2016.
*/
public class GetUsers {
public static void main(String[] args) throws IOException {
final String MANAGEMENT_TOKEN = "YOUR_MANAGEMENT_TOKEN";
OkHttpClient client = new OkHttpClient();
Request request = new Request.Builder()
.url("https://<YOUR_TENANT>.auth0.com/api/v2/users")
.get()
.addHeader("authorization", "Bearer " + MANAGEMENT_TOKEN)
.addHeader("cache-control", "no-cache")
.build();
Response response = client.newCall(request).execute();
System.out.println("All done: " + response.body().string());
}
}
You can use the Library Apache HTTP Client:
<dependency>
<groupId>org.apache.httpcomponents</groupId>
<artifactId>httpclient</artifactId>
<version>4.5.2</version>
</dependency>
and this code works fine :
HttpClient httpclient = new DefaultHttpClient();
URIBuilder builder = new URIBuilder("https://domain.auth0.com/api/v2/users");
HttpGet httpGet = new HttpGet(builder.build());
httpGet.setHeader("Accept", "application/json");
httpGet.setHeader("Content-type", "application/json");
httpGet.setHeader(
"Authorization",
"Bearer "+ token);
HttpResponse responseHttp = httpclient.execute(httpGet);
HttpEntity entity = responseHttp.getEntity();
BufferedReader rd = new BufferedReader(new InputStreamReader(entity.getContent()));
StringBuffer result = new StringBuffer();
String line = "";
while ((line = rd.readLine()) != null) {
result.append(line);
System.out.println(line);
}
This code you will give you only 50 users, if your users are over than 50 you have to use this URL :
https://domain.auth0.com/api/v2/users?per_page=50&page="+ pageNumber + "&include_totals=true"
and you can specify the number of users per page and the page number including the total of users.
the result of this code is a JSON, so the easiest way to parse it by using the Gson library:
<dependency>
<groupId>com.google.code.gson</groupId>
<artifactId>gson</artifactId>
<version>2.7</version>
</dependency>
and here is an example of parsing a Json String using the Gson Library :
public String parse(String jsonLine) {
JsonElement jelement = new JsonParser().parse(jsonLine);
JsonObject jobject = jelement.getAsJsonObject();
jobject = jobject.getAsJsonObject("data");
JsonArray jarray = jobject.getAsJsonArray("translations");
jobject = jarray.get(0).getAsJsonObject();
String result = jobject.get("translatedText").toString();
return result;
}
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