When working in Python I always have this simple utility function which returns the file name and line number from where the function is called:
from inspect import getframeinfo, stack
def d():
""" d stands for Debug. It returns the file name and line number from where this function is called."""
caller = getframeinfo(stack()[1][0])
return "%s:%d -" % (caller.filename, caller.lineno)
So in my code I simply put a couple debug lines like this to see how far we get before some error occurs:
print d()
# Some buggy code here
print d()
# More buggy code here
print d(), 'here is the result of some var: ', someVar
This works really well for me because it really helps debugging quickly.
I'm now looking for the equivalent in a node backend script. I was searching around but I can't find anything useful (maybe I'm looking for the wrong words?).
Does anybody know how I can create a Javascript/nodejs function which outputs the file name and line number from where the function is called? All tips are welcome!
The __filename represents the filename of the code being executed. This is the resolved absolute path of this code file. For a main program, this is not necessarily the same filename used in the command line. The value inside a module is the path to that module file.
To call a function, you can either pass its name and arguments to User. callFunction() or call the function as if it was a method on the User.
You can create an Error to get where the Error is, and its stack trace. Then you can put that into a function, to get the line where it is.
function thisLine() {
const e = new Error();
const regex = /\((.*):(\d+):(\d+)\)$/
const match = regex.exec(e.stack.split("\n")[2]);
return {
filepath: match[1],
line: match[2],
column: match[3]
};
}
console.log(thisLine());
This works for me in Google Chrome.
And also in node.
Note to @j08691's comment:
Both this and this seem to be using lineNumber
, which is not present (as far as I could test) in NodeJS.
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