How to get directory and file names while looping in shell script [duplicate]

Question

I'm doing a loop in files of directories and I need to get the current directory and file name on each step.

for f in /path/to/*/*.ext
do
  command "$d" "f" #! Here we send those two as parameters
done

I also need the file name without the extension ( .ext ). How should I make it?

Answer 1

You can use basename and dirname:

for f in /path/to/*/*.ext
do
  command "$(dirname "$f")" "$(basename "$f")" 
done

Another way using awk with .ext deletion:

for f in /path/to/*/*.ext ;do
   echo "$f"|awk -F\/ '{a=$NF;$NF="";gsub(".ext","",a)}{print $0" "a}' OFS=\/
done