How to get all links from the DOM?

Question

According to https://github.com/GoogleChrome/puppeteer/issues/628, I should be able to get all links from < a href="xyz" > with this single line:

const hrefs = await page.$$eval('a', a => a.href);

But when I try a simple:

console.log(hrefs)

I only get:

http://example.de/index.html

... as output which means that it could only find 1 link? But the page definitely has 12 links in the source code / DOM. Why does it fail to find them all?

Minimal example:

'use strict';
const puppeteer = require('puppeteer');

crawlPage();

function crawlPage() {
    (async () => {
	
	const args = [
            "--disable-setuid-sandbox",
            "--no-sandbox",
            "--blink-settings=imagesEnabled=false",
        ];
        const options = {
            args,
            headless: true,
            ignoreHTTPSErrors: true,
        };

	const browser = await puppeteer.launch(options);
        const page = await browser.newPage();
	await page.goto("http://example.de", {
            waitUntil: 'networkidle2',
            timeout: 30000
        });
     
	const hrefs = await page.$eval('a', a => a.href);
        console.log(hrefs);
		
        await page.close();
	await browser.close();
		
    })().catch((error) => {
        console.error(error);
    });;

}

Answer 1

In your example code you're using page.$eval, not page.$$eval. Since the former uses document.querySelector instead of document.querySelectorAll, the behaviour you describe is the expected one.

Also, you should change your pageFunctionin the $$eval arguments:

const hrefs = await page.$$eval('a', as => as.map(a => a.href));