How to get all lines after a line number

Question

I have a file like this:

string log 1 
string log 2
string match
string log 4
string match
string log 5
string log 6

I need to get all the lines after the last string match. How can I do it in bash?

Answer 1

First, find the last string match:

line=$(grep -n 'string match' myFile | cut -d: -f1 | tail -1)

Then, print all lines up to that last string match:

sed -n "1,${line}p" myFile

If you need all lines after last match:

sed -n "$((line+1))"',$p' myFile