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I'd like to put together a command that will print out a string of 32 hexadecimal digits. I've got a Python script that works:
python -c 'import random ; print "".join(map(lambda t: format(t, "02X"), [random.randrange(256) for x in range(16)]))' This generates output like:
6EF6B30F9E557F948C402C89002C7C8A Which is what I need.
On a Mac, I can even do this:
uuidgen | tr -d '-' However, I don't have access to the more sophisticated scripting languages ruby and python, and I won't be on a Mac (so no uuidgen). I need to stick with more bash'ish tools like sed, awk, /dev/random because I'm on a limited platform. Is there a way to do this?
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A random string is generated by first generating a stream of random numbers of ASCII values for 0-9, a-z and A-Z characters. All the generated integer values are then converted into their corresponding characters which are then appended to a StringBuffer.
To generate Random Hexadecimal Bytes, first, a random byte can be generated in decimal form using Java. util. Random. nextInt() and then it can be converted to hexadecimal form using Integer.
By string of hexadecimal digits what they mean is a combination of the digits 0-9 and characters A-F, just like how a binary string is a combination of 0's and 1's. Eg: "245FC" is a hexadecimal string.
If you have hexdump then:
hexdump -n 16 -e '4/4 "%08X" 1 "\n"' /dev/urandom should do the job.
Explanation:
-n 16 to consume 16 bytes of input (32 hex digits = 16 bytes).4/4 "%08X" to iterate four times, consume 4 bytes per iteration and print the corresponding 32 bits value as 8 hex digits, with leading zeros, if needed.1 "\n" to end with a single newline.
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If you are looking for a single command and have openssl installed, see below. Generate random 16 bytes (32 hex symbols) and encode in hex (also -base64 is supported).
openssl rand -hex 16 If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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