How to get a file name from a file's byte array?

Question

I have the bytes representing a file that I am transmitting over a network. Besides reconstructing the file manually on the file system, how can I get the information from the File, such as getName(), getPath(), etc?

In other words:

1. I start out with a File on machine A
2. I use FileUtils to turn the file into a byte array
3. I transmit that file over a network to machine B
4. On machine B, I want to reconstruct that byte[] into a File and run methods such as getName()

The following does not work

1. (File) bytes --> Does not convert
2. ((File) ((Object) bytes))) --> Does not convert either

I would really rather not create a new temporary file on the filesytem, although I know there are static File.createTemp available that will do that. I'd prefer to just keep it in memory, construct a new File object from the byte[] array, get the information I Need and be done.

Actually, what would be even better is an API that will take the byte[] and from it, directly get the file name by parsing the bits.

Answer 1

The byte[] that is returned by FileUtils.readFileToByteArray is only the file contents, nothing else.

You should create your own class that is Serializable that includes two fields: a byte[] for the file contents, and a java.io.File that has everything else you need. You then serialize/deserialize your class into byte[], which is transmitted.

Answer 2

The file contents and its name are two separate and independent things. While a specific file format could have metadata to store the name in the contents (similar to e.g. ID3 tags for MP3), in a typical file there is no way to know the name from byte [] contents. Also even if, it would be the name from a remote machine which may be invalid on the target platform.

If you want the name you need to transfer it separately.