For instance, the number 24 has prime factorization 2^3*3^1, and can be written in the following ways
1*24
2*12
2*2*6
2*3*4
2*2*2*3
3*8
4*6
I may have missed one but you get the idea.
I tried looking into the other thread How to find multiplicative partitions of any integer? but couldn't understand the answers in all honesty.
I don't need anyone to write code for me but rather I could really use some help creating an efficient algorithm for this (probably something recursive?).
I am coding in Python.
Your problem can be condensed into finding all of the partitions of a set, as each factor (prime and composite) can be represented as the product of the elements of a subset that makes up your partition.
I would represent the factors of your number as a list [2, 2, 2, 3]
(well, a set). Here are some possible partitions of this list:
[2] + [2, 2, 3]
[2, 2] + [2, 3]
[2] + [2] + [2, 3]
[3] + [2] + [2, 2]
If you multiply together each element of each subset, you will get a factor of the original number:
2 * 12
4 * 6
2 * 2 * 6
3 * 2 * 4
You might have to add in a special case for 1 * n
.
Here's a relevant question: How can I maximally partition a set?
And another relevant link: Generating the Partitions of a Set
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