Python/Django: automatically log when exceptions occur, including request info

Question

I have created a function log_error(request, traceback), which I call in my exceptions. This writes error information to the database. Now, before I open up every one of my views and add this in an exception handler, is there a way to automatically have all exceptions raise to a function, which then calls this?

I have seen this Python error logging, which says to write your own version of sys.excepthook. This function is automatically called when there is an exception. I tried this, but my_excepthook was not called even though I copy-pasted the solution into views.py and raised an error. However, I didn't try too hard because it's not getting all the information that I need, anyway. I also need request so I can log information abut the user, url, etc.

Maybe that's asking too much?

(I'm using Django, but this does not seem like a Django-specific thing) Edit: yes, it is.

Answer 1

J.F Sebastian's suggestion worked. This is a Django solution.

In settings.py MIDDLEWARE_CLASSES:

(I added it as the last one, not sure if this is right or will cause errors down the line. Works for now.)

'myapp.middleware.ExceptionMiddleware',

In myapp.middleware.py:

import traceback
class ExceptionMiddleware(object):
    def process_exception(self, request, exception):
        log_error(traceback, request)

That's it. log_error is my function and writes to the database. It also appears from the documentation https://docs.djangoproject.com/en/dev/howto/error-reporting/ that I can get the local variables as well as the request attributes.