How to generate a random 4 digit number not starting with 0 and having unique digits?

Question

This works almost fine but the number starts with 0 sometimes:

import random
numbers = random.sample(range(10), 4)
print(''.join(map(str, numbers)))

I've found a lot of examples but none of them guarantee that the sequence won't start with 0.

Answer 1

We generate the first digit in the 1 - 9 range, then take the next 3 from the remaining digits:

import random

# We create a set of digits: {0, 1, .... 9}
digits = set(range(10))
# We generate a random integer, 1 <= first <= 9
first = random.randint(1, 9)
# We remove it from our set, then take a sample of
# 3 distinct elements from the remaining values
last_3 = random.sample(digits - {first}, 3)
print(str(first) + ''.join(map(str, last_3)))

The generated numbers are equiprobable, and we get a valid number in one step.

Answer 2

Just loop until you have something you like:

import random

numbers = [0]
while numbers[0] == 0:
    numbers = random.sample(range(10), 4)

print(''.join(map(str, numbers)))