In Python, what is the difference between pass and return

Question

I have seen some code in Pinax and other django apps that instead of pass, an empty return statement is used. What is the difference and would it have any effect on, for example, the django code below that I am running? The code is a signal method that automatically saves the hashtags into taggit Tag objects for a tweet object.

I saw a question here about whether having or not having a return statement in PHP makes a difference in the interpreted bytecode, but I am not sure if it is relevant to Python.

import re TAG_REGEX = re.compile(r'#(?P<tag>\w+)')  def get_tagged(sender, instance, **kwargs):     """     Automatically add tags to a tweet object.     """     if not instance:         return # will pass be better or worse here?     post = instance     tags_list = [smart_unicode(t).lower() for t in list(set(TAG_REGEX.findall(post.content)))]     if tags_list:         post.tags.add(*tags_list)         post.save()     else:         return # will a pass be better or worse here? post_save.connect(get_tagged, sender=Tweet) 

Answer 1

if not instance:     return # will pass be better or worse here? 

Worse. It changes the logic. pass actually means: Do nothing. If you would replace return with pass here, the control flow would continue, changing the semantic of the code.

The purpose for pass is to create empty blocks, which is not possible otherwise with Python's indentation scheme. For example, an empty function in C looks like this:

void foo() { } 

In Python, this would be a syntax error:

def foo(): 

This is where pass comes handy:

def foo():     pass 

Answer 2

This illustrates some earlier answers.

def p():   "Executes both blocks."   if True:     print(1)     pass   if True:     print(2)     pass  def r():   "Executes only the first block."   if True:     print(1)     return   if True:     print(2)     return