How to 'forward' all-but-the-first-argument arguments of a function to another function?

Question

How do I forward the arguments from within a function to another function?

I have this:

function SomeThing(options) {
  function callback(callback_name) {
    if(options[callback_name]) {
      // Desiring to call the callback with all arguments that this function
      // received, except for the first argument.
      options[callback_name].apply(this, arguments);
    }
  }
  callback('cb_one', 99, 100);
}

What I get in the a argument is 'cb_one', but I want that it should be '99'.

var a = new SomeThing({
  cb_one: function(a,b,c) {
    console.log(arguments); // => ["cb_one", 99, 100]
    console.log(a);         // => cb_one
    console.log(b);         // => 99
    console.log(c);         // => 100
  }
});

How do I do this?

Answer 1

Use options[callback_name].apply(this, [].slice.call(arguments,1));

[].slice.call(arguments,1) converts the arguments ('array-like') Object into a real Array containing all arguments but the first.

[].slice.call may also be written as Array.prototype.slice.call.