How to find the device as LDPI MDPI HDPI or XHDPI [duplicate]

Question

Without any code snippet for the application, how to get screen resolution and length of the screen. How could I find whether the device is ldpi, mdpi , hdpi or xhdpi ?

Answer 1

Edit: use DisplayMetrics to get the density of the screen

getResources().getDisplayMetrics().densityDpi; 

this will return the int value that represents the following constants. DisplayMetrics.DENSITY_LOW ,DisplayMetrics.DENSITY_MEDIUM, DisplayMetrics.DENSITY_HIGH, DisplayMetrics.DENSITY_XHIGH

  int density= getResources().getDisplayMetrics().densityDpi;  switch(density) { case DisplayMetrics.DENSITY_LOW:    Toast.makeText(context, "LDPI", Toast.LENGTH_SHORT).show();     break; case DisplayMetrics.DENSITY_MEDIUM:      Toast.makeText(context, "MDPI", Toast.LENGTH_SHORT).show();     break; case DisplayMetrics.DENSITY_HIGH:     Toast.makeText(context, "HDPI", Toast.LENGTH_SHORT).show();     break; case DisplayMetrics.DENSITY_XHIGH:      Toast.makeText(context, "XHDPI", Toast.LENGTH_SHORT).show();     break; } 

This will return following constants based on thsi you can identify the device

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Try this

int screenSize = getResources().getConfiguration().screenLayout &         Configuration.SCREENLAYOUT_SIZE_MASK;  switch(screenSize) {     case Configuration.SCREENLAYOUT_SIZE_LARGE:         Toast.makeText(this, "Large screen",Toast.LENGTH_LONG).show();         break;     case Configuration.SCREENLAYOUT_SIZE_NORMAL:         Toast.makeText(this, "Normal screen",Toast.LENGTH_LONG).show();         break;     case Configuration.SCREENLAYOUT_SIZE_SMALL:         Toast.makeText(this, "Small screen",Toast.LENGTH_LONG).show();         break;     default:         Toast.makeText(this, "Screen size is neither large, normal or small" , Toast.LENGTH_LONG).show(); } 

Source Identifying screen resolutions