I want to find a nearest location from following database table
Address Latitude longitude Kathmandu 44600, Nepal 27.7 85.33333330000005 Los, Antoniterstraße 37.09024 -95.71289100000001 Sydney NSW, Australia 49.7480755 8.111794700000019 goa india 15.2993265 74.12399600000003
I have fetched this all data from Google Maps. Here I have to find nearest location from a place. Suppose I am at place Surkhet its latitude is 28.6 and longitude is 81.6, how can I find nearest place from the place Surkhet.
Heres is MySQL query and function which use to get distance between two latitude and longitude and distance will return in KM. SELECT getDistance($lat1,$lng1,$lat2,$lng2) as distance FROM your_table. Almost a decade later, this function gives THE SAME results as Google Maps distance measurement.
Finding locations nearby with MySQL
Here's the SQL statement that will find the closest 20 locations that are within a radius of 25 miles to the 37, -122 coordinate. It calculates the distance based on the latitude/longitude of that row and the target latitude/longitude, and then asks for only rows where the distance value is less than 25, orders the whole query by distance, and limits it to 20 results. To search by kilometers instead of miles, replace 3959 with 6371.
Table Structure :
id,name,address,lat,lng
NOTE - Here latitude = 37 & longitude = -122. So you just pass your own.
SELECT id, ( 3959 * acos( cos( radians(37) ) * cos( radians( lat ) ) * cos( radians( lng ) - radians(-122) ) + sin( radians(37) ) * sin( radians( lat ) ) ) ) AS distance FROM your_table_name HAVING distance < 25 ORDER BY distance LIMIT 0 , 20;
You can find details here.
SELECT id, ( 3959 * acos( cos( radians(37) ) * cos( radians( lat ) ) * cos( radians( lng ) - radians(-122) ) + sin( radians(37) ) * sin( radians( lat ) ) ) ) AS distance FROM markers HAVING distance < 25 ORDER BY distance LIMIT 0 , 20;
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