Menu
Code:
let names= ["Style","List","Raw"]; let results= names.find(x=> x.includes("s"); console.log(results); // How to get the names which contain "s" from the array names, currently, I am getting only one element as a result but i need all occurrences.
739
If you need the index of the found element in the array, use findIndex() . If you need to find the index of a value, use Array.prototype.indexOf() . (It's similar to findIndex() , but checks each element for equality with the value instead of using a testing function.)
To check if an array contains duplicates: Use the Array. some() method to iterate over the array. Check if the index of the first occurrence of the current value is NOT equal to the index of its last occurrence. If the condition is met, then the array contains duplicates.
sum() function in D3. js is used to return the sum of the given array's elements. If the array is empty then it returns 0. Parameters: This function accepts a parameters Array which is an array of elements whose sum are to be calculated.
You have to use filter at this context,
let names= ["Style","List","Raw"]; let results= names.filter(x => x.includes("s")); console.log(results); //["List"] If you want it to be case insensitive then use the below code,
let names= ["Style","List","Raw"]; let results= names.filter(x => x.toLowerCase().includes("s")); console.log(results); //["Style", "List"] To make it case in sensitive, we have to make the string's character all to lower case.
154
Use filter instead of find.
let names= ["Style","List","Raw"]; let results= names.filter(x => x.includes("s")); console.log(results); If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
