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I have to write a function that finds a product with given code from the given array. If product is found, a pointer to the corresponding array element is returned.
My main problem is that the given code should first be truncated to seven characters and only after that compared with array elements.
Would greatly appreciate your help.
struct product *find_product(struct product_array *pa, const char *code)
{
char *temp;
int i = 0;
while (*code) {
temp[i] = (*code);
code++;
i++;
if (i == 7)
break;
}
temp[i] = '\0';
for (int j = 0; j < pa->count; j++)
if (pa->arr[j].code == temp[i])
return &(pa->arr[j]);
}
385
Array elements are accessed using the Subscript variable, Similarly Structure members are accessed using dot [.] operator. Structure written inside another structure is called as nesting of two structures.
Use forEach() to find an element in an array The Array. prototype. forEach() method executes the same code for each element of an array. The code is simply a search of the index Rudolf (🦌) is in using indexOf.
An array of structres in C can be defined as the collection of multiple structures variables where each variable contains information about different entities. The array of structures in C are used to store information about multiple entities of different data types.
Why don't you just use strncmp in a loop?
struct product *find_product(struct product_array *pa, const char *code)
{
for (size_t i = 0; i < pa->count; ++i)
{
if (strncmp(pa->arr[i].code, code, 7) == 0)
return &pa->arr[i];
}
return 0;
}
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