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Lets say you filter for cpp files like so
$(wildcard **/*.cpp)
But you don't want files that contain the word foo and you don't want the file with the exact name bar.cpp
How does one use filter-out with multiple criteria?
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The file name of the target of the rule. If the target is an archive member, then ' $@ ' is the name of the archive file. In a pattern rule that has multiple targets (see Introduction to Pattern Rules), ' $@ ' is the name of whichever target caused the rule's recipe to be run.
The Function wildcard $(wildcard pattern ...) This string, used anywhere in a makefile, is replaced by a space-separated list of names of existing files that match one of the given file name patterns. If no existing file name matches a pattern, then that pattern is omitted from the output of the wildcard function.
Makefiles contain five kinds of things: explicit rules , implicit rules , variable definitions , directives , and comments . Rules, variables, and directives are described at length in later chapters. An explicit rule says when and how to remake one or more files, called the rule's targets.
This seems to work. Also recursively.
$(filter-out $(wildcard **/bar.cpp) $(wildcard **/*foo*), $(wildcard **/*.cpp))
Please also note Etan's simpler suggestion below. Leaving mine only for completeness.
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