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how to dynamically bind parameters using prepared statement?

I am trying to write prepared statement for user input. parameter numbers are variable depends on user input. Oam trying this code

PHP code:

$string          = "my name";
$search_exploded = explode( " ", $string );
$num             = count( $search_exploded );
$cart            = array();
for ( $i = 1; $i <= $num; $i ++ ) {
    $cart[] = 's';
}
$str          = implode( '', $cart );
$inputArray[] = &$str;
$j            = count( $search_exploded );
for ( $i = 0; $i < $j; $i ++ ) {
    $inputArray[] = &$search_exploded[ $i ];
}
print_r( $inputArray );
foreach ( $search_exploded as $search_each ) {
    $x ++;
    if ( $x == 1 ) {
        $construct .= "name LIKE %?%";
    } else {
        $construct .= " or name LIKE %?%";
    }
}
$query = "SELECT * FROM info WHERE $construct";
$stmt  = mysqli_prepare( $conn, $query );
call_user_func_array( array( $stmt, 'bind_param' ), $inputArray );
if ( mysqli_stmt_execute( $stmt ) ) {

    $result = mysqli_stmt_get_result( $stmt );
    if ( mysqli_num_rows( $result ) > 0 ) {
        echo $foundnum = mysqli_num_rows( $result );
        while( $row = mysqli_fetch_array( $result, MYSQLI_ASSOC ) ) {

            echo $id = $row['id'];
            echo $name = $row['name'];
        }
    }
}
    

When I print_r($inputArray), the output is:

Array ( [0] => ss [1] => my [2] => name ) 

There is no error showing in error log.

What is wrong?

like image 841
Vinay Avatar asked Mar 06 '23 22:03

Vinay


1 Answers

The % wrapping goes around the parameters, not the placeholders.

My snippet will be using object-oriented mysqli syntax instead of the procedural syntax that your code demonstrates.

First you need to set up the necessary ingredients:

  1. the WHERE clause expressions -- to be separated by ORs
  2. the data types of your values -- your values are strings, so use "s"
  3. the parameters to be bound to the prepared statement

I am going to combine #2 and #3 into one variable for simpler "unpacking" with the splat operator (...). The data type string must be the first element, then one or more elements will represent the bound values.

As a logical inclusion, if you have no conditions in your WHERE clause, there is no benefit to using a prepared statement; just directly query the table.

Code: (100% Tested / Successful Code)

$string = "my name";

$conditions = [];
$parameters = [''];
foreach (array_unique(explode(' ', $string)) as $value) {
    $conditions[] = "name LIKE ?";
    $parameters[0] .= 's';
    $parameters[] = "%{$value}%";
}
// $parameters now holds ['ss', '%my%', '%name%']

$query = "SELECT * FROM info";
if ($conditions) {
    $stmt = $conn->prepare($query . ' WHERE ' . implode(' OR ', $conditions));
    $stmt->bind_param(...$parameters);
    $stmt->execute();
    $result = $stmt->get_result();
} else {
    $result = $conn->query($query);
}
foreach ($result as $row) {
    echo "<div>{$row['name']} and whatever other columns you want</div>"; 
}

For anyone looking for similar dynamic querying techniques:

  • SELECT with dynamic number of values in IN()
  • INSERT dynamic number of rows with one execute() call
like image 106
mickmackusa Avatar answered Mar 08 '23 22:03

mickmackusa