How to do a Jquery Callback after form submit?

Question

I just did this -

 $("#myform").bind('ajax:complete', function() {

         // tasks to do 


   });

And things worked perfectly .

See this api documentation for more specific details.

I could not get the number one upvoted solution to work reliably, but have found this works. Not sure if it's required or not, but I do not have an action or method attribute on the tag, which ensures the POST is handled by the $.ajax function and gives you the callback option.

<form id="form">
...
<button type="submit"></button>
</form>

<script>
$(document).ready(function() {
  $("#form_selector").submit(function() {

    $.ajax({
     type: "POST",
      url: "form_handler.php",
      data: $(this).serialize(),
      success: function() {
        // callback code here
       }
    })

  })
})
</script>

You'll have to do things manually with an AJAX call to the server. This will require you to override the form as well.

But don't worry, it's a piece of cake. Here's an overview on how you'll go about working with your form:

• override the default submit action (thanks to the passed in event object, that has a preventDefault method)
• grab all necessary values from the form
• fire off an HTTP request
• handle the response to the request

First, you'll have to cancel the form submit action like so:

$("#myform").submit(function(event) {
    // Cancels the form's submit action.
    event.preventDefault();
});

And then, grab the value of the data. Let's just assume you have one text box.

$("#myform").submit(function(event) {
    event.preventDefault();
    var val = $(this).find('input[type="text"]').val();
});

And then fire off a request. Let's just assume it's a POST request.

$("#myform").submit(function(event) {
    event.preventDefault();
    var val = $(this).find('input[type="text"]').val();

    // I like to use defers :)
    deferred = $.post("http://somewhere.com", { val: val });

    deferred.success(function () {
        // Do your stuff.
    });

    deferred.error(function () {
        // Handle any errors here.
    });
});

And this should about do it.

Note 2: For parsing the form's data, it's preferable that you use a plugin. It will make your life really easy, as well as provide a nice semantic that mimics an actual form submit action.

Note 2: You don't have to use defers. It's just a personal preference. You can equally do the following, and it should work, too.

$.post("http://somewhere.com", { val: val }, function () {
    // Start partying here.
}, function () {
    // Handle the bad news here.
});

For MVC here was an even easier approach. You need to use the Ajax form and set the AjaxOptions

@using (Ajax.BeginForm("UploadTrainingMedia", "CreateTest", new AjaxOptions() { HttpMethod = "POST", OnComplete = "displayUploadMediaMsg" }, new { enctype = "multipart/form-data", id = "frmUploadTrainingMedia" }))
{ 
  ... html for form
}

here is the submission code, this is in the document ready section and ties the onclick event of the button to to submit the form

$("#btnSubmitFileUpload").click(function(e){
        e.preventDefault();
        $("#frmUploadTrainingMedia").submit();
});

here is the callback referenced in the AjaxOptions

function displayUploadMediaMsg(d){
    var rslt = $.parseJSON(d.responseText);
    if (rslt.statusCode == 200){
        $().toastmessage("showSuccessToast", rslt.status);
    }
    else{
        $().toastmessage("showErrorToast", rslt.status);
    }
}

in the controller method for MVC it looks like this

[HttpPost]
[ValidateAntiForgeryToken]
public JsonResult UploadTrainingMedia(IEnumerable<HttpPostedFileBase> files)
{
    if (files != null)
    {
        foreach (var file in files)
        {
            // there is only one file  ... do something with it
        }
        return Json(new
        {
            statusCode = 200,
            status = "File uploaded",
            file = "",
        }, "text/html");
    }
    else
    {
        return Json(new
        {
            statusCode = 400,
            status = "Unable to upload file",
            file = "",
        }, "text/html");
    }
}

I do not believe there is a callback-function like the one you describe.

What is normal here is to do the alterations using some server-side language, like PHP.

In PHP you could for instance fetch a hidden field from your form and do some changes if it is present.

PHP:

  $someHiddenVar = $_POST["hidden_field"];
    if (!empty($someHiddenVar)) {
        // do something 
    }

One way to go about it in Jquery is to use Ajax. You could listen to submit, return false to cancel its default behaviour and use jQuery.post() instead. jQuery.post has a success-callback.

$.post("test.php", $("#testform").serialize(), function(data) {
  $('.result').html(data);
});

http://api.jquery.com/jQuery.post/