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how to disable an option already selected in another <select>?

I have five HTML selects with different values, but the options have the same text. How do I compare the text options, instead of the values, and disable the the respective option in every other select? For example, if I have:

<select name="options[70]" id="select_70">
  <option value="1" price="0"> test-1 </option>
  <option value="2" price="0"> test-2 </option>
  <option value="3" price="0"> test-3 </option>
</select>
<select name="options[71]" id="select_71">
  <option value="4" price="0"> test-1 </option>
  <option value="5" price="0"> test-2 </option>
  <option value="6" price="0"> test-3 </option>
</select>
<select name="options[72]" id="select_72">
  <option value="7" price="0"> test-1 </option>
  <option value="8" price="0"> test-2 </option>
  <option value="9" price="0"> test-3 </option>
</select>
<select name="options[73]" id="select_73">
  <option value="10" price="0"> test-1 </option>
  <option value="11" price="0"> test-2 </option>
  <option value="12" price="0"> test-3 </option>
</select>
<select name="options[74]" id="select_74">
  <option value="13" price="0"> test-1 </option>
  <option value="14" price="0"> test-2 </option>
  <option value="15" price="0"> test-3 </option>
</select>

Suppose the user selects the option test-1 in the last select. This should disable the corresponding option in the other selects. How can I achieve that?

like image 482
Marcello Infoweb Avatar asked Dec 15 '22 08:12

Marcello Infoweb


2 Answers

If I understand you properly, this might be it:

var $selects = $('select');
$selects.on('change', function() {
    var $select = $(this), 
        $options = $selects.not($select).find('option'),
        selectedText = $select.children('option:selected').text();

    var $optionsToDisable = $options.filter(function() {
        return $(this).text() == selectedText;
    });

    $optionsToDisable.prop('disabled', true);
});

//to apply initial selection
$selects.eq(0).trigger('change');

jsFiddle: example

like image 79
Igor Dymov Avatar answered Dec 17 '22 22:12

Igor Dymov


Expanding on @IgorDymov's answer (credit should go to him), here's probably what I'd do (see fiddle):

var $selects = $('select');
$selects.on('change', function() {
    $("option", $selects).prop("disabled", false);
    $selects.each(function() {
        var $select = $(this), 
            $options = $selects.not($select).find('option'),
            selectedText = $select.children('option:selected').text();
        $options.each(function() {
            if($(this).text() == selectedText) $(this).prop("disabled", true);
        });
    });
});

$selects.eq(0).trigger('change');

That way we completely refresh the selections each time a new one is made, which means properties become re-enabled again. You'll notice in the fiddle I reduced the number of selects and increased the number of options so that you don't get trapped in a situation where all options are disabled at the same time, I think that makes most sense.

like image 38
Ian Clark Avatar answered Dec 17 '22 20:12

Ian Clark