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In the following code snippet, how do I find the exit code of make? Specifically, I need to know if make has failed or succeeded. Thanks for any inputs.
process = pexpect.spawn("/bin/bash")
process.expect("make\r")
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Pexpect is a Python module for spawning child applications and controlling them automatically. Pexpect can be used for automating interactive applications such as ssh, ftp, passwd, telnet, etc. It can be used to a automate setup scripts for duplicating software package installations on different servers.
The important methods of pexpect. spawn class are expect(). This method waits for the child process to return a given string. The pattern specified in the except method will be matched all through the string.
spawn. close() would close the pty which in turn would send SIGHUP to the shell which in turn would terminate (kill) the shell unless the shell is ignoring SIGHUP . It's like you close the PuTTY (or gnome-terminal , ...) window when the shell is still running.
sendline() is just a convenience wrapper of send() . send() must be used if you don't want to press ENTER.
pexpect doesn't know about the make command - it is just sending text to bash. So you need to use bash's mechanism for determining exit code - the value of $?. So you want something like this:
process.sendline("make") # Note: issue commands with send, not expect
process.expect(prompt)
process.sendline("echo $?")
process.expect(prompt)
exitcode = process.before.strip()
I had to use pexpect in my latest project and wanted to get the exit code, couldn't find the solution easily, as this is the top result in google I'm adding my solution to this.
process = pexpect.spawn(command, cwd=work_dir)
process.expect(pexpect.EOF)
output = process.before
process.close()
exit_code = process.exitstatus
I have the output saved as well, because I am running bash scripts and the exit code is saved in the exit_code variable.
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