I have a dataset with 11 columns with over a 1000 rows each. The columns were labeled V1, V2, V11, etc.. I replaced the names with something more useful to me using the "c" command. I didn't realize that row 1 also contained labels for each column and my actual data starts on row 2.
Is there a way to delete row 1 and decrement?
The most easiest way to drop columns is by using subset() function. In the code below, we are telling R to drop variables x and z. The '-' sign indicates dropping variables. Make sure the variable names would NOT be specified in quotes when using subset() function.
You can print a backspace, and it will delete a character on the same line. Printing a RET character "\r" (in some front ends) will take you to the start of line to overwrite it.
Keep the labels from your original file like this:
df = read.table('data.txt', header = T)
If you have columns named x and y, you can address them like this:
df$x df$y
If you'd like to actually delete the first row from a data.frame, you can use negative indices like this:
df = df[-1,]
If you'd like to delete a column from a data.frame, you can assign NULL to it:
df$x = NULL
Here are some simple examples of how to create and manipulate a data.frame in R:
# create a data.frame with 10 rows > x = rnorm(10) > y = runif(10) > df = data.frame( x, y ) # write it to a file > write.table( df, 'test.txt', row.names = F, quote = F ) # read a data.frame from a file: > read.table( df, 'test.txt', header = T ) > df$x [1] -0.95343778 -0.63098637 -1.30646529 1.38906143 0.51703237 -0.02246754 [7] 0.20583548 0.21530721 0.69087460 2.30610998 > df$y [1] 0.66658148 0.15355851 0.60098886 0.14284576 0.20408723 0.58271061 [7] 0.05170994 0.83627336 0.76713317 0.95052671 > df$x = x > df y x 1 0.66658148 -0.95343778 2 0.15355851 -0.63098637 3 0.60098886 -1.30646529 4 0.14284576 1.38906143 5 0.20408723 0.51703237 6 0.58271061 -0.02246754 7 0.05170994 0.20583548 8 0.83627336 0.21530721 9 0.76713317 0.69087460 10 0.95052671 2.30610998 > df[-1,] y x 2 0.15355851 -0.63098637 3 0.60098886 -1.30646529 4 0.14284576 1.38906143 5 0.20408723 0.51703237 6 0.58271061 -0.02246754 7 0.05170994 0.20583548 8 0.83627336 0.21530721 9 0.76713317 0.69087460 10 0.95052671 2.30610998 > df$x = NULL > df y 1 0.66658148 2 0.15355851 3 0.60098886 4 0.14284576 5 0.20408723 6 0.58271061 7 0.05170994 8 0.83627336 9 0.76713317 10 0.95052671
You can use negative indexing to remove rows, e.g.:
dat <- dat[-1, ]
Here is an example:
> dat <- data.frame(A = 1:3, B = 1:3) > dat[-1, ] A B 2 2 2 3 3 3 > dat2 <- dat[-1, ] > dat2 A B 2 2 2 3 3 3
That said, you may have more problems than just removing the labels that ended up on row 1. It is more then likely that R has interpreted the data as text and thence converted to factors. Check what str(foo)
, where foo
is your data object, says about the data types.
It sounds like you just need header = TRUE
in your call to read in the data (assuming you read it in via read.table()
or one of it's wrappers.)
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