How to define a template member function of a template class [duplicate]

Question

Possible Duplicate:
How do I define a template function within a template class outside of the class definition?

I'm struggling with the syntax for the case where I have a template member function within a template class:

template <typename T> class Foo {     void Bar(const T * t);     template <typename T2> void Bar(const T2 * t); };  template <typename T> void Foo<T>::Bar(const T * t) {     // ... no problem ... }  template <typename T> void Foo<T>::Bar<typename T2>(const T2 * t) {     // ... this is where I'm tearing my hair out ... } 

The first member function is fine, but the template member function which handles types other than the base type of the template class is where I am having problems. For the above case I get the following errors:

template_problem.cpp:12: error: parse error in template argument list template_problem.cpp:12: error: expected ‘,’ or ‘...’ before ‘*’ token template_problem.cpp:12: error: ISO C++ forbids declaration of ‘T2’ with no type template_problem.cpp:12: error: template-id ‘Bar<<expression error> >’ in declaration of primary template template_problem.cpp:12: error: prototype for ‘void Foo<T>::Bar(int)’ does not match any in class ‘Foo<T>’ template_problem.cpp:4: error: candidates are: template<class T> template<class T2> void Foo::Bar(const T2*) template_problem.cpp:7: error:                 void Foo<T>::Bar(const T*) template_problem.cpp:12: error: template definition of non-template ‘void Foo<T>::Bar(int)’ 

and I've also tried every other syntax variation I can think of for the template version of Bar.

Answer 1

template<typename T> template<typename T2> void Foo<T>::Bar(const T2* t)  {      // stop tearing your hair out } 

Answer 2

template <typename T> template <typename T2>  void Foo<T>::Bar(const T2 * t) {     // ... this is where I'm tearing my hair out ... } 

Ugly isn't it.