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So I have this string:
[email protected]:/home/some/directory/file
I just want to extract the directory address meaning I only want the bit after the ":" character and get:
/home/some/directory/file
thanks.
I need a generic command so the cut command wont work as the $var variable doesn't have a fixed length.
755
To cut by character use the -c option. This selects the characters given to the -c option. This can be a list of comma separated numbers, a range of numbers or a single number. Where your input stream is character based -c can be a better option than selecting by bytes as often characters are more than one byte.
In Bash (and ksh, zsh, dash, etc.), you can use parameter expansion with % which will remove characters from the end of the string or # which will remove characters from the beginning of the string. If you use a single one of those characters, the smallest matching string will be removed.
The cut command in UNIX is a command for cutting out the sections from each line of files and writing the result to standard output. It can be used to cut parts of a line by byte position, character and field. Basically the cut command slices a line and extracts the text.
`sed` command is another option to remove leading and trailing space or character from the string data. The following commands will remove the spaces from the variable, $myVar using `sed` command. Use sed 's/^ *//g', to remove the leading white spaces. There is another way to remove whitespaces using `sed` command.
Using sed:
$ [email protected]:/home/some/directory/file
$ echo $var | sed 's/.*://'
/home/some/directory/file
This might work for you:
echo ${var#*:}
See Example 10-10. Pattern matching in parameter substitution
29
This will also do.
echo $var | cut -f2 -d":"
For completeness, using cut
cut -d : -f 2 <<< $var
And using only bash:
IFS=: read a b <<< $var ; echo $b
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