How to create an infinitely long sequence in Kotlin

Question

I'm looking for something like

val allInts = (1..).asSequence()

so I could, for example

allInts.take(5)

Answer 1

JB's answer is good but you could also go with

generateSequence(1, Int::inc)

if you're into the whole brevity thing.

Answer 2

If you need an infinite sequence you should use the new sequence function:

val sequence = sequence {
  while (true) {
    yield(someValue())
  }
}

Previous answer

Use Int.MAX_VALUE as the upper bound. You cannot have an integer greater than Int.MAX_VALUE.

val allInts = (1..Int.MAX_VALUE).asSequence()