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how to create a range of random decimal numbers between 0 and 1

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python

how do I define decimal range between 0 to 1 in python? Range() function in python returns only int values. I have some variables in my code whose number varies from 0 to 1. I am confused on how do I put that in the code. Thank you

I would add more to my question. There is no step or any increment value that would generate the decimal values. I have to use a variable which could have a value from 0 to 1. It can be any value. But the program should know its boundary that it has a range from 0 to 1. I hope I made myself clear. Thank you

http://docs.python.org/library/random.html

like image 803
zingy Avatar asked Jul 28 '11 17:07

zingy


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4 Answers

This will output decimal number between 0 to 1 with step size 0.1

import numpy as np
mylist = np.arange(0, 1, 0.1)
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user78692 Avatar answered Nov 12 '22 16:11

user78692


If you are looking for a list of random numbers between 0 and 1, I think you may have a good use of the random module

>>> import random
>>> [random.random() for _ in range(0, 10)]
[0.9445162222544106, 0.17063032908425135, 0.20110591438189673,
 0.8392299590767177, 0.2841838551284578, 0.48562600723583027,
 0.15468445000916797, 0.4314435745393854, 0.11913358976315869,
 0.6793348370697525]
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brandizzi Avatar answered Nov 12 '22 17:11

brandizzi


for i in range(100):
    i /= 100.0
    print i

Also, take a look at decimal.

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Karoly Horvath Avatar answered Nov 12 '22 15:11

Karoly Horvath


def float_range(start, end, increment):
    int_start = int(start / increment)
    int_end = int(end / increment)
    for i in range(int_start, int_end):
        yield i * increment
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Mark Ransom Avatar answered Nov 12 '22 16:11

Mark Ransom