I am trying to create an array of arrays of arrays etc..., except I don't know how many nested levels deep it needs to be until runtime.
Depending on the input, I might need either int[]
, int[][]
, int[][][][][][]
, or anything else. (For context, I am trying to construct an N-dimensional grid for a cellular automaton, where N is passed as a parameter.)
I don't have any code for you because I have no idea how to go about this; I suspect is not possible at all using just arrays. Any help, or alternative solutions, would be appreciated.
Java's arrays are actually built of nested references, similar to a double ** 2D array representation in C. You are right but from the point of view of the code using it, this doesn't matter as long as the total number of elements in the array does not go beyond the 2 Gig 32 bit limit.
Here is how we can initialize a 2-dimensional array in Java. int[][] a = { {1, 2, 3}, {4, 5, 6, 9}, {7}, }; As we can see, each element of the multidimensional array is an array itself. And also, unlike C/C++, each row of the multidimensional array in Java can be of different lengths.
Creating a Nested Array: Let's create nested arrays using those three methods to get an idea of Nested Arrays. This one is just equating the variable to the array. Second one is using the array method new Array() . And the last one is using the Array() which is similar to the new Array() .
You could do this with an Object[], limiting its members to either Object[] or int[].
For example, here's an array that goes three levels deep in one part, and two levels deep in another:
Object[] myarray = new Object[] {
new Object[] { new int[] { 1, 2 },
new int[] { 3, 4 }},
new int[] { 5, 6 }
};
After you've created it, you may want to access members. In your case, you know the depth N up front, so you know at what depth to expect an Object[] and at what depth to expect an int[].
However, if you didn't know the depth, you could use reflection to determine whether a member is another Object[] level or a leaf int[].
if ( myarray[0] instanceof Object[] ) {
System.out.println("This should print true.");
}
EDIT:
Here's a sketch [untested so far, sorry] of a method that access a member of an array of known depth, given an array of indices. The m_root member can be an Object[] or an int[]. (You could relax this further to support scalars.)
public class Grid {
private int m_depth;
private Object m_root;
...
public int get( int ... indices ) {
assert( indices.length == m_depth );
Object level = m_root;
for ( int i = 0; i + 1 < m_depth; ++i ) {
level = ((Object[]) level)[ indices[i] ];
}
int[] row = (int[]) level;
return row[ indices[m_depth - 1] ];
}
}
This should be achievable using Object[]
, since arrays are objects:
int[] arr = {1,2,3};
int[] arr2 = {1,2,3};
int[] arr3 = {1,2,3};
int[] arr4 = {1,2,3};
Object[] arr5 = {arr, arr2}; // basically an int[][]
Object[] arr6 = {arr3, arr4}; // basically an int[][]
Object[] arr7 = {arr5, arr6}; // basically an int[][][]
// etc.
Note that one array doesn't have to contain arrays of the same dimensions:
Object[] arr7 = {arr5, arr};
To prevent this (and to allow for easier access to the data), I suggest writing a class which has an Object
member (which will be your int[]
or Object[]
) and a depth variable and some nice functions to give you access to what you want.
ArrayList
s will also work:
ArrayList array = new ArrayList();
array.add(new ArrayList());
array.add(new ArrayList());
((ArrayList)array.get(0)).add(new ArrayList());
// etc.
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