I have lines like these, and I want to know how many lines I actually have...
09:16:39 AM all 2.00 0.00 4.00 0.00 0.00 0.00 0.00 0.00 94.00 09:16:40 AM all 5.00 0.00 0.00 4.00 0.00 0.00 0.00 0.00 91.00 09:16:41 AM all 0.00 0.00 4.00 0.00 0.00 0.00 0.00 0.00 96.00 09:16:42 AM all 3.00 0.00 1.00 0.00 0.00 0.00 0.00 0.00 96.00 09:16:43 AM all 0.00 0.00 1.00 0.00 1.00 0.00 0.00 0.00 98.00 09:16:44 AM all 0.00 0.00 0.00 0.00 0.00 0.00 0.00 0.00 100.00 09:16:45 AM all 2.00 0.00 6.00 0.00 0.00 0.00 0.00 0.00 92.00
Is there a way to count them all using linux commands?
If you are in *Nix system, you can call the command wc -l that gives the number of lines in file.
The wc command is used to find the number of lines, characters, words, and bytes of a file. To find the number of lines using wc, we add the -l option. This will give us the total number of lines and the name of the file.
Use grep -n string file to find the line number without opening the file.
Use wc
:
wc -l <filename>
This will output the number of lines in <filename>
:
$ wc -l /dir/file.txt 3272485 /dir/file.txt
Or, to omit the <filename>
from the result use wc -l < <filename>
:
$ wc -l < /dir/file.txt 3272485
You can also pipe data to wc
as well:
$ cat /dir/file.txt | wc -l 3272485 $ curl yahoo.com --silent | wc -l 63
To count all lines use:
$ wc -l file
To filter and count only lines with pattern use:
$ grep -w "pattern" -c file
Or use -v to invert match:
$ grep -w "pattern" -c -v file
See the grep man page to take a look at the -e,-i and -x args...
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