I have a class:
class Symbol_t {
public:
Symbol_t( const char* rawName ) {
memcpy( m_V, rawName, 6 * sizeof( char ) );
};
string_view strVw() const {
return string_view( m_V, 6 );
};
private:
char m_V[6];
}; // class Symbol_t
and there is a lib-func that I can't modify:
extern bool loadData( const string& strSymbol );
If there is a local variable:
Symbol_t symbol( "123456" );
When I need to call loadData, I dare not do it like this:
loadData( string( symbol.strVw().begin(), symbol.strVw().end() ) );
I have to do like this:
string_view svwSym = symbol.strVw();
loadData( string( svw.begin(), svw.end() ) );
My question: Is the first method correct? or I must use the second one?
Because I think that in Method 1, the iterators I passed to the constructor of std::string, are of two Different string_vew objects, and theoretically the result is undefined, even though we would get expected result with almost all of the C++ compilers.
Any hints will be appreciated! thanks.
The std::string_view, from the C++17 standard, is a read-only non-owning reference to a char sequence. The motivation behind std::string_view is that it is quite common for functions to require a read-only reference to an std::string-like object where the exact type of the object does not matter.
So, frequently, you can pass string_view by reference and get away with it. But you should pass string_view by value, so that the compiler doesn't have to do those heroics on your behalf. And so that your code-reviewer doesn't have to burn brain cells pondering your unidiomatic decision to pass by reference.
In C++, you should use the string header. Write #include <string> at the top of your file. When you declare a variable, the type is string , and it's in the std namespace, so its full name is std::string .
There is no functionality difference between string and std::string because they're the same type.
There is no need to use the c'tor taking a range. std::string
has a constructor that operates in terms of std::string_view
, number 10 in the list. The effect of which is
template < class T > explicit basic_string( const T& t, const Allocator& alloc = Allocator() );
Implicitly converts t to a string view sv as if by
std::basic_string_view<CharT, Traits> sv = t;
, then initializes the string with the contents ofsv
, as if bybasic_string(sv.data(), sv.size(), alloc)
. This overload only participates in overload resolution ifstd::is_convertible_v<const T&, std::basic_string_view<CharT, Traits>>
is true andstd::is_convertible_v<const T&, const CharT*>
is false.
Since both conditions hold for std::string_view
itself, we can write the call to loadData
as simply:
loadData( std::string( symbol.strVw() ) );
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