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I have: "0xE94C827CEB" in hex but as a string.
Which is: 1002011000043 (dd mm yyyy HH mm ss)
Unfortunately I don't know how to do the conversion if I only have it in string format, and I don't have a Convert.ToLong("0xE94C827CEB", 16) function because I'm using the .NET Micro Framework (also, don't have NumberStyles namespace available.)
Is there a function out there that will convert this for me?
Thanks
939
There are many methods for converting a String to a Long data type in Java which are as follows: Using the parseLong() method of the Long class. Using valueOf() method of long class. Using constructor of Long class.
In order to convert a hex string into a normal string, the hex string has to be converted into a byte array, which is indexed and converted into smaller hex strings of two digits. The smaller hex strings are then concatenated into a normal string. For some values, a two digit hex string will start with a zero.
Hex, like decimal, combines a set of digits to create large numbers. It just so happens that hex uses a set of 16 unique digits.
We can convert String to long in java using Long. parseLong() method.
For those of you looking for the answer using the full .NET framework for pc.
long answer = Convert.ToInt64("E94C827CEB",16);
see: MSDN Documentation
177
I don't know of any function to do it, but I think you can do it quite simply by splitting the hex string and passing each part through Convert.ToInt32():
int part1 = Convert.ToInt32("E9", 16)
int part2 = Convert.ToInt32("4C827CEB", 16) //the last 4 bytes
long result = part1 * 4294967296 + part2 //4294967296 being 2^32. Result = 1002011000043
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