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How to convert list of dict to dict. Below is the list of dict
data = [{'name': 'John Doe', 'age': 37, 'sex': 'M'},
{'name': 'Lisa Simpson', 'age': 17, 'sex': 'F'},
{'name': 'Bill Clinton', 'age': 57, 'sex': 'M'}]
to
data = {'John Doe': {'name': 'John Doe', 'age': 37, 'sex': 'M'},
'Lisa Simpson': {'name': 'Lisa Simpson', 'age': 17, 'sex': 'F'},
'Bill Clinton': {'name': 'Bill Clinton', 'age': 57, 'sex': 'M'}}
465
Since python dictionary is unordered, the output can be in any order. To convert a list to dictionary, we can use list comprehension and make a key:value pair of consecutive elements. Finally, typecase the list to dict type.
We can convert a nested list to a dictionary by using dictionary comprehension. It will iterate through the list. It will take the item at index 0 as key and index 1 as value.
To convert a list to a dictionary using the same values, you can use the dict. fromkeys() method. To convert two lists into one dictionary, you can use the Python zip() function. The dictionary comprehension lets you create a new dictionary based on the values of a list.
For odd items we do the same but starting at index 1 . If we zip those two lists together we obtain a list of (key, value) that we can pass the return value to the dict constructor. Might add a map(str, ....) to the second part to exactly match the desired result.
A possible solution using names as the new keys:
new_dict = {}
for item in data:
name = item['name']
new_dict[name] = item
With python 3.x you can also use dict comprehensions for the same approach in a more nice way:
new_dict = {item['name']:item for item in data}
As suggested in a comment by Paul McGuire, if you don't want the name in the inner dict, you can do:
new_dict = {}
for item in data:
name = item.pop('name')
new_dict[name] = item
With python 3.3 and above, you can use ChainMap
A ChainMap groups multiple dicts or other mappings together to create a single, updateable view. If no maps are specified, a single empty dictionary is provided so that a new chain always has at least one mapping.
from collections import ChainMap
data = dict(ChainMap(*data))
If the dicts wouldnt share key, then you could use:
dict((key,d[key]) for d in data for key in d)
Probably its better in your case to generate a dict with lists as values?
newdict={}
for k,v in [(key,d[key]) for d in data for key in d]:
if k not in newdict: newdict[k]=[v]
else: newdict[k].append(v)
This yields:
>>> newdict
`{'age': [37, 17, 57], 'name': ['John Doe', 'Lisa Simpson', 'Bill Clinton'], 'sex': ['M', 'F', 'M']}`
Try this approach:
dict((key, val) for k in data for key, val in k.items())
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