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I read the text format using below code,
f = open("document.txt", "r+", encoding='utf-8-sig')
f.read()
But the type of f is _io.TextIOWrapper. But I need type as string to move on.
Please help me to convert _io.TextIOWrapper to string.
762
TextIOWrapper class The file object returned by open() function is an object of type _io. TextIOWrapper . The class _io. TextIOWrapper provides methods and attributes which helps us to read or write data to and from the file.
The Python: "TypeError: '_io. TextIOWrapper' object is not callable" occurs when we try to call a file object as if it were a function. To solve the error, make sure you don't have any clashes between function and variable names and access properties on the file object instead.
You need to use the output of f.read().
string = f.read()
I think your confusion is that f will be turned into a string just by calling its method .read(), but that's not the case. I don't think it's even possible for builtins to do that.
For reference, _io.TextIOWrapper is the class of an open text file. See the documentation for io.TextIOWrapper.
By the way, best practice is to use a with-statement for opening files:
with open("document.txt", "r", encoding='utf-8-sig') as f:
string = f.read()
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