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We can convert int to String in java using String. valueOf() and Integer. toString() methods.
The %d format specifier expects an int argument, but you're passing a double . Using the wrong format specifier invokes undefined behavior. To print a double , use %f .
The strtol library function in C converts a string to a long integer. The function works by ignoring any whitespace at the beginning of the string, converting the next characters into a long integer, and stopping when it comes across the first non-integer character.
Implement itoa() function in CThe standard itoa() function converts input number to its corresponding C-string using the specified base. Prototype: The prototype of the itoa() is: char* itoa(int value, char* buffer, int base);
Use sprintf():
int someInt = 368;
char str[12];
sprintf(str, "%d", someInt);
All numbers that are representable by int will fit in a 12-char-array without overflow, unless your compiler is somehow using more than 32-bits for int. When using numbers with greater bitsize, e.g. long with most 64-bit compilers, you need to increase the array size—at least 21 characters for 64-bit types.
Making your own itoa is also easy, try this :
char* itoa(int i, char b[]){
char const digit[] = "0123456789";
char* p = b;
if(i<0){
*p++ = '-';
i *= -1;
}
int shifter = i;
do{ //Move to where representation ends
++p;
shifter = shifter/10;
}while(shifter);
*p = '\0';
do{ //Move back, inserting digits as u go
*--p = digit[i%10];
i = i/10;
}while(i);
return b;
}
or use the standard sprintf() function.
That's because itoa isn't a standard function. Try snprintf instead.
char str[LEN];
snprintf(str, LEN, "%d", 42);
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