I have an image I
which is of type double
. I want to convert the image from double
to uint8
. I have tried using both:
I=uint8(I)
I=im2uint8(I)
.When I use the imshow(I)
command, I get only a black image and nothing else. What am I doing wrong?
uint8 is used unsigned 8 bit integer. And that is the range of pixel. We can't have pixel value more than 2^8 -1. Therefore, for images uint8 type is used. Whereas double is used to handle very big numbers.
Y = uint8( X ) converts the values in X to type uint8 . Values outside the range [0,28-1] map to the nearest endpoint.
J = im2uint8( I ) converts the grayscale, RGB, or binary image I to uint8 , rescaling or offsetting the data as necessary. If the input image is of class uint8 , then the output image is identical. If the input image is of class logical , then im2uint8 changes true-valued elements to 255.
The im2uint8
function assumes that your double
image is scaled to the range [0,1]
. If your image has values larger than 1
or smaller than 0
, these values will be clipped. See the following example:
im2uint8([-1 0 0.5 1 2])
ans =
0 0 128 255 255
The solution is to scale the input image to [0,1]
by subtracting the minimum value and dividing by the total range:
I = (I - min(I(:))) / (max(I(:)) - min(I(:)));
I = im2uint8(I);
imshow(I);
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