Menu
I am trying to decode a gob output that I am sending through another fasthttp endpoint and receiving an error Fasthttp endpoint(encode []string through gob) ----> Fasthttp endpoint( receive and decode)
buffer := &bytes.Buffer{}
buffer = ctx.PostBody()
backToStringSlice := []string{}
gob.NewDecoder(buffer).Decode(&backToStringSlice)
I am getting error: ctx.PostBody() (type []byte) as type *bytes.Buffer in assignment
how do I convert []byte to *bytes.Buffer.
Any help is appreciated.
383
Like a byte is a group of 8 bits, a buffer is a group of a pre-defined number of bytes. If we have a group of 3 bytes, this could either represent 3 values between 0 and 255, but also one single value between 0 and 16777216 (2563).
To create a byte in Go, assign an ASCII character to a variable. A byte in Golang is an unsigned 8-bit integer. The byte type represents ASCII characters, while the rune data type represents a broader set of Unicode characters encoded in UTF-8 format.
There are several differences between a byte array and ByteBuffer class in Java, but the most important of them is that bytes from byte array always reside in Java heap space, but bytes in a ByteBuffer may potentially reside outside of the Java heap in case of direct byte buffer and memory mapped files.
In go language, the buffer belongs to the byte package of the Go language, and we can use these package to manipulate the byte of the string. For example, suppose we have a string. We can read the length of the string with the len function, which will return the numeric length, but what if the strings are too large.
NewBuffer will do what you want
package main
import (
"fmt"
"bytes"
)
func main() {
foo:=[]byte{65,66,67}
z:=bytes.NewBuffer(foo)
fmt.Println("Hello, playground", foo, z)
}
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
