I need to convert the numbers 1
to 255
(address
) into hex values from 01
to FE
(hexAddress
).
There must be a leading 0 for values from 01
to 0F
, the letters must be uppercase, and there cannot be a 0x
prepended to the hex value.
Edit: This question is not a duplicate. The question that it is cited as a duplicate of has an accepted answer that does not work for this situation, nor does it fully explain how it works.
Use "%02x" . The two means you always want the output to be (at least) two characters wide. The zero means if padding is necessary, to use zeros instead of spaces.
The format() method of String class in Java 5 is the first choice. You just need to add "%03d" to add 3 leading zeros in an Integer. Formatting instruction to String starts with "%" and 0 is the character which is used in padding. By default left padding is used, 3 is the size and d is used to print integers.
Approach 1 – Using Format() Method in Java The string. format() is used to print the number of places of a hexadecimal value and store the value in a string. %02X is used to print add two spaced between two hexadecimal values(of a hexadecimal (X)).
String hexAddress = String.format("%1$02X",address);
%1
means these flags are for the first argument. In this case, there is only one argument.
$
separates the argument index from the flags
0
is a flag that means pad the result with leading zeros up to the specified bit width.
2
is the bit width
X
means convert the number to hex, and use uppercase letters. x
would convert to hex and use lowercase letters.
You can read more about the different possible arguments by examining the Java Formatter class.
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