I want to take an integer (that will be <= 255), to a hex string representation
e.g.: I want to pass in 65
and get out '\x41'
, or 255
and get '\xff'
.
I've tried doing this with the struct.pack('c',
65)
, but that chokes on anything above 9
since it wants to take in a single character string.
hex() function is one of the built-in functions in Python3, which is used to convert an integer number into it's corresponding hexadecimal form. Syntax : hex(x) Parameters : x - an integer number (int object) Returns : Returns hexadecimal string.
Python hex() function is used to convert an integer to a lowercase hexadecimal string prefixed with “0x”. We can also pass an object to hex() function, in that case the object must have __index__() function defined that returns integer. The input integer argument can be in any base such as binary, octal etc.
You are looking for the chr
function.
You seem to be mixing decimal representations of integers and hex representations of integers, so it's not entirely clear what you need. Based on the description you gave, I think one of these snippets shows what you want.
>>> chr(0x65) == '\x65' True >>> hex(65) '0x41' >>> chr(65) == '\x41' True
Note that this is quite different from a string containing an integer as hex. If that is what you want, use the hex
builtin.
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