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I have the following dynamic object that I'm getting from a third party library:
IOrderStore os = ss.GetService<IOrderStore>();
IOrderInfo search = os.Orders.Where(t => t.Number == "test").FirstOrDefault();
IOrder orderFound = os.OpenOrder(search, true);
dynamic order = (dynamic)orderFound;
dynamic requirements = order.Title.Commitments[0].Requirements;
I need to parse it to a JSON string.
I tried this (using JSON.net):
string jsonString = JsonConvert.SerializeObject(requirements);
return jsonString;
But I get a seemingly corrupted JSON string, as below:
[{"$id":"1"},{"$id":"2"},{"$id":"3"},{"$id":"4"},{"$id":"5"},{"$id":"6"},{"$id":"7"},{"$id":"8"},{"$id":"9"},{"$id":"10"},{"$id":"11"},{"$id":"12"},{"$id":"13"},{"$id":"14"},{"$id":"15"}]
The object contains multiple properties, and not just the 'id'.
Any advice?
439
However, sometimes we have fixed and dynamic properties mixed in a single JSON object. We can treat this kind of structure as a dynamic object.
List<String> columns = new List<String>{"FirstName","LastName"}; var jsonObj = new {}; for(Int32 i=0;i<columns. Count();i++) jsonObj[col[i]]="Json" + i; And the final json object should be like this: jsonObj={FirstName="Json0", LastName="Json1"};
A common way to deserialize JSON is to first create a class with properties and fields that represent one or more of the JSON properties. Then, to deserialize from a string or a file, call the JsonSerializer. Deserialize method.
Have you tried using var instead of dynamic?
// Use "var" in the declaration below.
var requirements = order.Title.Commitments[0].Requirements;
string jsonString = JsonConvert.SerializeObject(requirements);
When you only want to deserialize requirements without doing anything else with it then there is no need to use it dynamically.
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