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How to convert a date HH: MM: SS in second with bash?
Knowing that this is a date that I recovered in a file so I can't take it in another format.
I have two variables $DateStart and $DateEnd and i would like the difference between both.
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The command date +%S will print the current amount of seconds. What is the bash script you are using this in?
Bash Date format MM-DD-YYYY To format date in MM-DD-YYYY format, use the command date +%m-%d-%Y or printf "%(%m-%d-%Y)T\n" $EPOCHSECONDS .
Sample shell script to display the current date and time #!/bin/bash now="$(date)" printf "Current date and time %s\n" "$now" now="$(date +'%d/%m/%Y')" printf "Current date in dd/mm/yyyy format %s\n" "$now" echo "Starting backup at $now, please wait..." # command to backup scripts goes here # ...
date +%S. Displays seconds [00-59] date +%N. Displays in Nanoseconds.
date +%s
returns the current datetime in seconds since 1970-01-01 00:00:00 UTC
if you want to get a given datetime in seconds since 1970-01-01 00:00:00 UTC, for example:
kent$ date -d"2008-08-08 20:20:20" +%s
1218219620
to get diff in seconds, you just get the two dates in seconds, and do a s1-s2
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On a Mac you can convert a date into another date with a combination of the -j and -f option:
$ date -j -f '%Y-%m-%d %H:%M:%S' "2016-02-22 20:22:14" '+%s'
1456168934
Where -j suppresses changing the system clock,
-f <fmt> gives the format to use for parsing the given date,
"2016-02-22 20:22:14" is the input date and
+<fmt> is the output format.
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