How to convert a bool to a string in Go?

Question

use the strconv package

docs

strconv.FormatBool(v)

func FormatBool(b bool) string FormatBool returns "true" or "false"
according to the value of b

The two main options are:

1. strconv.FormatBool(bool) string
2. fmt.Sprintf(string, bool) string with the "%t" or "%v" formatters.

Note that strconv.FormatBool(...) is considerably faster than fmt.Sprintf(...) as demonstrated by the following benchmarks:

func Benchmark_StrconvFormatBool(b *testing.B) {
  for i := 0; i < b.N; i++ {
    strconv.FormatBool(true)  // => "true"
    strconv.FormatBool(false) // => "false"
  }
}

func Benchmark_FmtSprintfT(b *testing.B) {
  for i := 0; i < b.N; i++ {
    fmt.Sprintf("%t", true)  // => "true"
    fmt.Sprintf("%t", false) // => "false"
  }
}

func Benchmark_FmtSprintfV(b *testing.B) {
  for i := 0; i < b.N; i++ {
    fmt.Sprintf("%v", true)  // => "true"
    fmt.Sprintf("%v", false) // => "false"
  }
}

Run as:

$ go test -bench=. ./boolstr_test.go 
goos: darwin
goarch: amd64
Benchmark_StrconvFormatBool-8       2000000000           0.30 ns/op
Benchmark_FmtSprintfT-8             10000000           130 ns/op
Benchmark_FmtSprintfV-8             10000000           130 ns/op
PASS
ok      command-line-arguments  3.531s

In efficiency is not too much of an issue, but genericity is, just use fmt.Sprintf("%v", isExist), as you would for almost all the types.

you may use strconv.FormatBool like this:

package main

import "fmt"
import "strconv"

func main() {
    isExist := true
    str := strconv.FormatBool(isExist)
    fmt.Println(str)        //true
    fmt.Printf("%q\n", str) //"true"
}

or you may use fmt.Sprint like this:

package main

import "fmt"

func main() {
    isExist := true
    str := fmt.Sprint(isExist)
    fmt.Println(str)        //true
    fmt.Printf("%q\n", str) //"true"
}

or write like strconv.FormatBool:

// FormatBool returns "true" or "false" according to the value of b
func FormatBool(b bool) string {
    if b {
        return "true"
    }
    return "false"
}