Is there a way to iterate over a slice in reverse in Go?

Question

No there is no convenient operator for this to add to the range one in place. You'll have to do a normal for loop counting down:

s := []int{5, 4, 3, 2, 1}
for i := len(s)-1; i >= 0; i-- {
   fmt.Println(s[i])
}

You can also do:

s := []int{5, 4, 3, 2, 1}
for i := range s {
        fmt.Println(s[len(s)-1-i]) // Suggestion: do `last := len(s)-1` before the loop
}

---

Output:

1
2
3
4
5

Also here: http://play.golang.org/p/l7Z69TV7Vl

Variation with index

for k := range s {
        k = len(s) - 1 - k
        // now k starts from the end
    }

How about use defer:

s := []int{5, 4, 3, 2, 1}
for i, _ := range s {
   defer fmt.Println(s[i])
}

One could use a channel to reverse a list in a function without duplicating it. It makes the code nicer in my sense.

package main

import (
    "fmt"
)

func reverse(lst []string) chan string {
    ret := make(chan string)
    go func() {
        for i, _ := range lst {
            ret <- lst[len(lst)-1-i]
        }
        close(ret)
    }()
    return ret
}

func main() {
    elms := []string{"a", "b", "c", "d"}
    for e := range reverse(elms) {
        fmt.Println(e)
    }
}

I guess this is the easiest way to reverse arrays.:

package main

import "fmt"

// how can we reverse write the array
func main() {

    arr := [...]int{1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
    revArr := [len(arr)]int{} // making empty array for write reverse

    for i := range arr {
        revArr[len(arr)-1-i] = arr[i]
    }

    fmt.Println(revArr)
}

https://play.golang.org/p/QQhj26-FhtF